What is structure of SO3 (in solid state) at room temperature?

 In solid phase SO₃ exist at room temperature and have two different structures i.e. alpha-SO₃ chain structure and gama- (SO₃)₃ cyclic structure (a trimer) like ice structure.

 

S-S bond is presents in? (IIT)

 (a) S₂O₄^2-  (b) S₂O₆^2-  (c) S₂O₇^2- (d) both (a) & (b) 

SOLUTION:

What is structure of SO3 (in solid state) at room temperature?

What is stucture of (H2S2O3) thiosulphuric acid?

What is stucture of (H2S2O8) Peroxydisulphuric acid or marshall's acid?

How can determine presence of Oxylinkage present in a given oxygen acids?

Condition of presence of Oxylinkage in oxyacids:

If the calculated /average oxidation state of central atom of Oxy acid/oxy anion ,Oxide having two or more central atom is found to be one of its common  oxidation state , then Oxy linkage will be present.

For example:

H₆P₄O₁₃: calculated oxidation state is = +5

Common oxidation state of "P" is = +3, +5

It means calculated oxidation state matches with one of the common oxidation state so there are Oxy linkage present in H₆P₄O₁₃.

 

Note: this rule is not applicable for H₂N₂O₂ Hyponitrous acid, H₂S₂O₃ Thiosulphuric acid and H₂S₂O₅ Disulphurous acid or Pyrosulphurous acid.

Related Questions:

S-S bond is presents in? (IIT)

S-S bond is presents in? (IIT)

What is structure of SO3 (in solid state) at room temperature?

What is stucture of (H2S2O3) thiosulphuric acid?

What is stucture of (H2S2O8) Peroxydisulphuric acid or marshall's acid?

What is use of Orthoboric acids?

Orthoboric acid is used in manufacture of ENAMELS and Glazes for pottery and as disinfectant in medicine.

Why does aniline not undergo friedel crafts reaction?

 Aniline is basic due to the presence of lone pair of electron on the nitrogen atom of amine group. Where as AlCl₃ is a Lewis acid which is used as catalyst in friedel craft reaction. 

Al has a empty orbital  so it accept lone pair electron from amine group hence nitrogen atom of amine acquired positive charge and ring become deactivating. Due to this reason aniline does not undergoes friedel craft reaction.

Related Questions:

1. How is base strength related to the availabihty of the electron-pair?
2. Amines are more basic than ammonia why?
3. What is relative basic strength order 1° amines , 2°amines and 3° amines ? Explain:
4. Give an explanation for the fact that Guanidine NH=C(CH3)2 is a stronger base than most of amines?
5. Arrange in correct order of basic Character of aniline, pyrrol, pyridine and piperidine?
6. What is correct basicity order of pyridine, pyridazine, pyrimidine and pyrazine ?
7. Give an explanation for the fact that Guanidine NH=C(CH3)2 is a stronger base than most of amines?
8. Arrange in correct order of basic Character of aniline, pyrrol, pyridine and piperidine?
9. What is correct basicity order of pyridine, pyridazine, pyrimidine and pyrazine ?
10. Why pyridine is more basic than Pyrrole?
11. Why pyrimidine is less basic than pyridine?
12. Imidazole is more basic than pyridine? Why?
13. Biological Important of Imidazole and structure:
14. Pyridine is almost 1 million times less basic than piperidine? Why?
15. Cyclohexylamine amine is the stronger base than Aniline? Why?
16. Tetrahydroquinoline amine is the stronger base than Tetrahydroisoquinoline? Why?
17. Arrange the following in the order of increasing basicity : p-Toluidine, N, N-Dimethyl-p-toluidine, p-Nitroaniline, Aniline. (I.I.T.1986)
18. Arrange the following in the increasing order of their acid strength : Methyl amine, Dimethyl amine, Aniline, N-methyl aniline (I.I.T, 1988).