Henry & Smith equation:
The percentage ionic character in covalent compound arises due to the electronegative difference of bonding atoms. And percentage ionic character of covalent bond calculates by Henry and Smith equation;
Solved Questions:
Henry & Smith equation:
The percentage ionic character in covalent compound arises due to the electronegative difference of bonding atoms. And percentage ionic character of covalent bond calculates by Henry and Smith equation;
Solved Questions:
Stevenson & Schromaker Equation:
Covalent radius of heterogeneous molecule like A-B etc determine by Stevenson & Schromaker Equation, if atoms are formed different type of covalent bond i.e. on atom is more electronegative than the other combined atom. Then the covalent radius is calculated by the relation given by Stevenson & Schromaker, given as:
For a diatomic Hetero molecule:
Bond Length (lA-B) = rA + rB- 0.09(XA-XB)
Where XA= Electronegativity of more electronegative atom
Where XB= Electronegativity of less electronegative atom
Solved Questions:
For a diatomic Hetero molecule:
Bond Length (l) = rA + rB- 0.09(XA-XB)
Where XA= Electronegativity of more electronegative atom
Where XB= Electronegativity of less electronegative atom
For a diatomic Hetero molecule:
Bond Length (l) = rA + rB- 0.09(XA-XB)
Where XA= Electronegativity of more electronegative atom
Where XB= Electronegativity of less electronegative atom
(1)-Classification
of Elements & Periodicity in properties
(2) Structure of atom and Electronic configuration
(3)-Chemical bonding
& Molecular Structures
3.1 Chemical Bonds
3.2 Ionic Bond
3.3 Covalent bond (sigma and pi Bond)
3.4 Coordinate bond
3.5 Valence Bond Theory
3.5 Hybridization
3.6 VSEPR Theory
3.6 MOT
(4)-General Inorganic
Chemistry (G.Ino.C)
3.1 Dipole Moment
3.2 Fajan’s Rule
3.3 Resonance
3.4 D-Orbital resonance
3.5 Bent’s rule of hybridization
3.6 Drago’s rule: No need of hybridization
3.7 Back bond
3.8 Bridge Bond: Multi-centered Bond
3.9 Vander Waal’s force
3.10 Hydrogen Bond
3.11 Metallic Bond
5-Acid-Base Concepts/theories
4.1 Arrhenius Acid–Base concept
4.2 Bronsted Lowery Acid-base concept:
4.3 Lewis Acid-Base concepts:
4.4 The Solvent System (Self or Auto Ionization of Solvent):
4.5 The Lux-Flood Acids-base concepts:
4.6 The Usanovich Acid-base concepts:
6-Oxides (Acid
anhydrides)
5.1 Classification of oxides: (On the Basis of oxygen content):
5.2 Classification of oxides: (On the basis of Acid-Base Interaction):
7-Oxy acids and its Salts
6.1 Oxy acids of Boron:
6.2 Oxy acids of Silicon:
6.3 Oxy acids of Nitrogen:
6.4 Oxy acids of Phosphorous:
6.5 Oxy acids of Sulphur:
6.6 Oxy acids of Chlorine:
(8)-Type of
inorganic reactions
(9)-Hydrolysis
Mechanism
8.1 Hydrolysis of Halides of 13th group:
8.2 Hydrolysis of Halides of 14th group:
8.3 Hydrolysis of Halides of 15th group:
8.4 Hydrolysis of Halides of 16th group:
8.5 Hydrolysis of Interhalogen compounds:
8.6 Hydrolysis of Halides of 18th group:
8.7 Hydrolysis of peroxy acids:
8.8 Hydrolysis of Oxides:
8.9 Hydrolysis of Carbides:
8.10 Hydrolysis of Nitrides:
8.11 Hydrolysis of Hydrides:
8.12 Hydrolysis of phosphides:
8.13 Hydrolysis of sulphides:
8.14 Hydrolysis of Silicides:
8.15 Hydrolysis of Borides:
8.16 Hydrolysis of Phosphides:
(10)-Effect of heat on compounds (acids, bases and Salts)
9.1 Thermal stability of salts
9.2 Thermal Decomposition Reactions
(11)- The
Coordination compounds
(12)- Quantitive Analysis (Salts Analysis):
(A) Both are planer and non polar
(B) Both have aromatic character
(C) Both have ppi-ppi bond formed
by pairing of unpaired electrons
(D) Electrophilic subtitution reaction occurs at B3N3H6
SOLUTION:(
A,B,D) In Boraxine ion boron and oxygen atom alternatively
combined to form six member ring and also each boron atom linked with extra
oxygen atoms. Both boron and oxygen atoms have sp2 hybridization (by Back
bonding and all oxygen atom involved in back bonding) and planer structure due
to fact ring become aromatic but due to sp3 hybrisation of oxygen atom molecule
become polar.
In
Borazine (Inorganic Benzene) molecule, nitrogen is more electro negative than
the boron. Nitrogen acquires partial negative charge and boron acquires partial
positive charge and back bonding take place between boron and nitrogen.
Even
though Borazine and Benzene have same stricture their chemical properties are
different.
(1)
Organic benzene is C6H6 while Inorganic benzene is
Borazine having chemical formula B3N3H6
(2)
Borazine is more reactive than Benzene with repect to electrophic
addition reactions due to high
polarity (B-N polar bond) of Borazine plecules.
(3) Aromaticity
of borazine is less than benzene hence it is less reactive
toward Eectrophilic substitution reactions than Benzene.
Hence options (A), (B) and (D) is correct But Option (C) is Incorrect Both
have pi-bond due to back bonding not due
to formed by pairing of unpaired electrons
Why aqueous
solution of AlCl3 is acidic in nature ?
What happen when
aq AlCl3 react with Acid or Base?
Although
anhydrous aluminium chloride is covalent but its aqueous solution is ionic in
nature. Why?
Why BF3 do not
exist as dimer?. Explain.
Why B-F bond
length in BF3 is shorter (130 pm) than B-F bond Iength in BF4- (143 pm)?.
Explain.
B-F bond length
in BF3 is shorter than B-F bond length in (BF4)- why?
What is product
of reaction between diborane (B2H6) and ammmonia (NH3)?
Why methylation
of Diborane (B2H6) replace four hydrogen only ?
What is use of
Orthoboric acids?
What is basicity
of "Boric acid" ?
Why Boric acid
exist in solid state ?
What is
structure of solid Ortho Boric acid ?
What is effect
of heat on Borax?
What is the
structure of trimetaboric acid and trimetaborate ion?
What is the
Sodium per borate ,give the structure and its uses?
Why aqueous
solution of borax reacts with two moles of acids ?
What is the
molecular formula of Borax ?
Why Boric acid
become strong acid in the presence of cis 1,2-diol or 1,3-diol ?
Why Borazine is
more reactive than benzene towards Electrophic Aromatic substitution reactions
?
Why Borazine
(B3N3H6) is also known as inorganic benzene ?.
Four-center
two-electron bond (4C-2e Bond): Structure of AlCl3:
What is the difference between the structure of AlCl3 and diborane?
The strength of a Lewis acid is a measure of its ability to attract a pair of electrons on a molecule that is behaving as a Lewis base. Fluorine is more electronegative than chlorine, so it appears that three fluorine atoms should withdraw electron density from the boron atom, leaving it more positive.This would also happen to some extent when the peripheral atoms are chlorine, but chlorine is less electronegative than fluorine. On this basis, we would expect BF3 to be a stronger Lewis acid. However,in the BF3 molecule, the boron atom uses sp2 hybrid orbitals, which leaves one empty 2p orbital that is perpendicular to the plane of the molecule. The fluorine atoms have filled 2p orbitals that can overlap with the empty 2p orbital on the boron atom to give some double bond character (Back Bond) to the B–F bonds.
As a result of the contribution by resonance structures having some double bond character, the boron atom in BF3 is not as electron deficient as it is in BCl3. And hence BCl3 a stronger Lewis acid than BF3
(1) Oxygen of Me-O-Me is sp3 hybridised so C-O-C bond angle is more than 109’28” approx 110” due to crowding of methyl group.
(2) In disilyl ether , oxygen is Sp2 hybridised and planer due to
back bonding between oxygen and silicon atom. In this back bonding lone pair of oxygen atom
donate to the vacant d orbital of silicon atom due to this fact bond lengths of Si-O is
decrease and increases (approx 140”).
(3) In (Ph)3Si-O-Si(Ph)3 compounds Si-O-Si bond angle is Approx 180 due to back bonding and hybridisation is Sp.
Nitrogen (N) atom in trimethyl amine [N(CH3)3] is sp3 hybridised and tetrahedral ( bond angle ~107) due to non bonding electron pair of N is localised (more basic). On the other hand N atom of trisilyl amine [N(SiH3)3] is sp2 hybridised and trigonal planner (bond angle~120).This is due to the participation of non-bondlng pair of N into pπ-dπ back banding. Due to this delocalization of non-bonding electron pair of N in trisilyl amine it is also less basic
Generally neutral atom donates only one lone pair to back bonding because after that, electron density on that atom itself highly reduced but the compound [(CF3)2-Al-O-Al-(CF3)2] is a rare example of two lone pair donation.