(a) S2O42- (b) S2O62- (c) S2O72- (d) both (a) & (b)
SOLUTION:
Friday, November 20, 2020
Thursday, November 19, 2020
How can determine presence of Oxylinkage present in a given oxygen acids?
Condition
of presence of Oxylinkage in oxyacids:
If the calculated /average oxidation state of central atom of Oxy acid/oxy anion ,Oxide having two or more central atom is found to be one of its common oxidation state , then Oxy linkage will be present.
For
example:
H6P4O13: calculated
oxidation state is = +5
Common oxidation state of "P" is = +3, +5
It means calculated oxidation state matches with one
of the common oxidation state so there are Oxy linkage present in H6P4O13.
Note:
this rule is not applicable for H2N2O2
Hyponitrous acid, H2S2O3
Thiosulphuric acid and H2S2O5
Disulphurous acid or Pyrosulphurous acid.
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S-S bond is presents in? (IIT)
What is use of Orthoboric acids?
Orthoboric acid is used in manufacture of ENAMELS and Glazes for pottery and as disinfectant in medicine.
Why does aniline not undergo friedel crafts reaction?
Aniline is basic due to the presence of lone pair of electron on the nitrogen atom of amine group. Where as AlCl3 is a Lewis acid which is used as catalyst in friedel craft reaction.
Al has a empty orbital so it accept lone pair electron from amine group hence nitrogen atom of amine acquired positive charge and ring become deactivating. Due to this reason aniline does not undergoes friedel craft reaction.
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- Arrange the following in the order of increasing basicity : p-Toluidine, N, N-Dimethyl-p-toluidine, p-Nitroaniline, Aniline. (I.I.T.1986)
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What is the oxidation state of Cr in K3CrO8?
In the given structure all the oxygen atoms involve in peroxy linkage so oxygen atom are in(-1) Oxidation State. Hence the Oxidation number of Cr ion in this Compound is = +5
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