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Monday, January 18, 2021

What is structure of BeH2 in solid state ?

BeH2 is covalent hydride and having polymeric structure in solid state in which beryllium atoms are bonded together by three centre-two electrons(3c-2e) bridge bond which also know as banana bond and all the H-Be-H bond angle are below 109.28’

But in gaseous BeH2 exist in dimeric form in which Be atoms are sp2 hybridised, planer  and non polar(dipole moment zero).

Related Questions:



What is structure of diborane?

(1)  B2H6 contains 4-Terminal H are bonded by Sigma bond and  remaining 2-H are bridging hydrogen's and of these are broken then dimer become monomer.

(2) Boron undergoes sp3 hybridisation 3 of its sp3 hybridised orbitals contain one( e¯) each and fourth sp3 hybrid orbital is vacant.

(3) 3-(Three) of these sp3 hybrid orbitals get overlapped by s orbitals of 3-hydrogen atoms.

(4) One of the sp3 hybrid orbitals which have been overlapped by s orbital of hydrogen gets overlapped by vacant sp3 hybrid orbital. Of 2nd Boron atom. And it's vice versa.

(5) By this two types of overlapping take place 4 (sp3– s) overlap bonds and 2(sp2 – s – sp3) overlap bonds.


(6) H is held in this bond by forces of attraction from B and This bond is called 3 centred two electron bonds (3C-2e bond) . Also called Banana bonds. Due to repulsion between the two hydrogen nuclei, the delocalised orbitals of bridges are bent away from each other on the middle giving the shape of banana.

(7) The two bridging hydrogens are in a plane and perpendicular to the rest four hydrogen atoms.

ILLUSTRATED EXAMPLE (1): In Diborane

(A) 4 bridged hydrogens and two terminal hydrogen are present

(B) 2 bridged hydrogens and four terminal hydrogen are present

(C) 3 bridged and three terminal hydrogen are present

(D)None of the above

 

ILLUSTRATED EXAMPLE (2): Which one of the following statements is not true regarding diborane?

(A) It has two bridging hydrogens and four perpendicular to the rest.

(B) When methylated, the product is Me4B2H2.

(C) The bridging hydrogens are in a plane and perpendicular to the rest.

(D ) All the B–H bond distances are equal

 

ILLUSTRATED EXAMPLE (3): The structure of diborane (B2H6) contains

(A) Four (2C–2e–) bonds and two (2C–3e–) bonds

(B) Two (2C–2e–) bonds and two (3C–2e–) bonds

(C) Four (2C–2e–) bonds and four (3C– 2e–) bonds

(D ) None of these


ILLUSTRATED EXAMPLE (4): The molecular shapes  of diborane is shown:

Consider the following statements for diborane:

1. Boron is approximately sp3 hybridised

2. B–H–Bangle is 180°

3. There are two terminal B–H bonds for each boron atom

4. There are only 12 bonding electrons available

Of these statements:

(A ) 1, 3 and 4 are correct                  (B) 1, 2 and 3 are correct

(C) 2, 3 and 4 are correct                    (D) 1, 2 and 4 are correct



Sunday, January 17, 2021

Structure of Al2(CH3)3 and also explain the bridge bonding in Al2(CH3)3?

Structural features of Dimer of Al(CH3)3:


 

What is the structure of (O2F2) oxygen fluoride

The compound id produced as result of glow dischage through amixture of O2 and F2 at -180 to -190 degree (c). As should be expected. O2F2 is an extremely reactive fluorinating agent. Under the conditions that produce OF2, small and O4F2 are produced, but these unstable compounds decomposed at liquid nitrogen temperatures.

Why Bond length of O-O is greater in H2O2 than O2F2?

Electronegativity of F is much more than hydrogen and also hybridization of oxygen atoms in of H2O2 and O2F2 both have (sp3) same and hence we can apply bent’s rule.

According bent’s rule more eletronegative atoms reduce % s-character (or increases % p-character vice versa) of those hybride orbital in which they attach. So in case of O2F2 % s-character of those hybride orbital decrease which have  flourine while % p-character increases in same way % s-character of  remaing hybride orbital inceases and p-character decreases hence its bond length also (bond length is directly proportional to % p-character) decreases.  hence O-O bond length in O2F2 is shorter thane H2O2.

Related Questions:

What is Bent’s rule of hybridization?

Which of the following compound have longest (S=O)bond length , O=SF2, O=SCl2, O=SBr2.

Oxides of Halogens;

Halogens and oxygen they do not combine directly with oxygen due to high electron affinity of both halogens and oxygen but their oxides with oxygen can be prepared indirectly.

The compounds of oxygen with fluorine are called as fluorides (not a oxide) because fluorine is more electronegative than oxygen. Most of these compounds are endothermic and unstable and are likely to explode resulting in the formation of more stable products.

The compounds of chlorine ,bromine and Iodine with oxygen are called oxide because electronegtivity of oxygen is greater than these. And the common oxides of halogens are X2O, X2O3, X2O5, and X3O7 (common oxidation state of 17th group) and uncommon oxides are ClO2 (+4) and ClO3/Cl2O6 etc.

 

Flourine

O.S.

Chlorine

Bromine

Iodine

OF2 &O2F2

(+1) /X2O

Cl2O

Br2O

 

 

(+3)/X2O3

 

 

 

 

(+4)

ClO2/Cl2O4

BrO2

I2O4

 

(+5)/X2O5

 

 

I2O5

 

(+6)

ClO3/Cl2O6

BrO3

 

 

(+7)/X2O7

Cl2O7

 

 

 

All the oxides are powerful oxidizing agents and decompose explosively when they are given mechanical shock or heat.

Structure of  chlorine oxides:

Structure of dichlorine heptaoxide:                   

Avarage oxidation state of Chlorine in Cl2O7 is one of the common oxidation state of the chlorine so there is (Cl-O-Cl) Oxy-linkage will be present. And one of oxygen atom is shared by both of chlorine atoms and rest of the oxygen atoms equally distributed.

The whole molecule dichlorine heptaoxide (Cl2O7) is non planer and polar and oxygen atom of (Cl-O-Cl) oxy-linkage does not involve in delocalization due to maximum repulsion hence two Cl-O bond have equal length and bond order may be/equal to one while other six Cl=O bond have eqaual bond length

In dichlorine heptaoxide (Cl2O7) , two ClO4 group connected with an oxygen atom which is sp3 hybridised (non planer) and bond angle may be expected 109⦁28’ but actually due to the presence of two lone pair on oxygen atom the Cl-O-Cl bond angle deviated from ideal and it may be greater (119⦁) than ideal bond angle.

Question (1): Number of sigma  and pi bonds present in Cl2O7 is/ are ....?

Number of sigma and pi bond present in Cl2O7 are (8) and (6) repectively.

Question(2):What is the anhydride of  HClO4 ?

Cl2​O7​ is the anhydride of  HClO4

Question (3):Number of equivalent Cl-O bond in Cl2O7 is/are….

Number of equivalent Cl-O bond in Cl2O7 are (2) two.

 

Question(4):Number of equivalent Cl=O bond in Cl2O7 is/are….

Number of equivalent Cl=O bond in Cl2O7 are (6) six.

Related Questions:




Trisilyl amine, N(SiH3)3 is planar whereas trimethyl amines N(CH3)3 is pyramidal. Explain why?.