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Showing posts sorted by relevance for query back bond. Sort by date Show all posts

Wednesday, December 26, 2018

BRIDGE BONDING-MULTI-CENTERED BOND:

Formation of bridge bonds is properly explained by MOT. According to which these bonds are formed by filling electrons into molecular orbital’s which lies over three nuclei hence such bonds are called specified as three centre bonds.
Bond angle between bridge bonds is less than bond angle between terminal bonds.
Bridge bonds are longer than terminal bonds
Bond energy of
3C-2e bond is found to be higher than 2C-2e bond for same substitute. It may also be true for 4C-4e bond.
During formation of bridge bond empty atomic orbitals of central atom participate in hybridization.
ILLUSTRATIVE EXAMPLES (1):
ILLUSTRATIVE EXAMPLE (2): BCl3 do not dimerised due to back bonding


ILLUSTRATIVE EXAMPLE (3): AlCl3   will have also    very less back bonding due to crowding  
ILLUSTRATIVE EXAMPLE (4): Steric crowding will there in B(CH3)3
IMPORTANT NOTES:
(1) If there is no steric crowding and back bonding in a molecules then bridge bond formed and molecules dimerised and stabilized and dimerisation are more stable than back bonding.
(2) Most of the electron deficient compound attains stability by performing back bonding or they undergo dimerisation provided certain conditions are fulfilled
(3) BCl3 ,BBr3 BI3 and B(Me)3 although  they are electron deficient compound but do not undergo dimerisation  because  of steric factor in demmeric formed

TYPE OF BRIDGE BOND:
(1) 3C-2e Bond Or Banana Bond         (2) 4C-4e Bond

(1) 3C-2e BOND OR BANANA BOND:

ILLUSTRATIVE EXAMPLE (5): FORMATION OF B2H6:
(1) Formation of 3C-2e bond in B2H6 is best explain by MOT and total number of bond in B2H6 is 6 (3C-2e=2 and 3C-4e=4)
(2) Bridge bonds are longer than terminal bond because at bridge bonds electrons are delocalized at three centres
(3) Bond energy (441kj/mole) of B-H-B bond is greater than bond energy (381 K j/mole) of   B-H bond.
(4) Hybridization of B atom is sp3, so non planer, and non polar (U=0)
(5)  B2H6 Methylated up to B2H2 Me4
(6) B2H6 is hypovalent molecule hence act as Lewis acid and undergoes two type of cleavage when react with Lewis base:

(A) UNSYMETRICAL CLEAVAGE: 
B2H6 Undergo unsymmetrical cleavage with small size strong Lewis base like NH3 NH2Me and NH (Me) 2 etc.

(B) SYMETRICAL CLEAVAGE:
B2H6 undergoes symmetrical cleavage with large size weak Lewis base like PH3, PF3,Me3N , OEt , OMe3, pyridine , THF , Thiophene , SMe2 ,Set2

(2) 3C-4e BOND or 3C-4e BRIDGE BOND: 
AL2Cl6 Dimmerised by 3C-4e bond bridge bond:

Al2Cl6 is neither hypovalent nor hypovalent rather its octet is complete. We will used  MOT here  it cannot act as Lewis acid  due to crowding in spite   having vacant d orbital’s   however Alcl3  act as Lewis acid .
Al2Cl6 contains six bond having two bridge bond(3c-4e) and four bond is (2C-2e)
Boron do not formed bridge bond because boron experience steric crowding.

REASON OF DIMERISATION:
(1) By formation of 3C-2e bond
(2) By formation of 3C-4e bond
(3) By pairing of unpaired electrons.

ILLUSTRATIVE EXAMPLE (6): Which of the following molecule is/are dimerized by co-ordination bond?
(A) AlCl3                     (B) BeCl2                    (C) ICl3                         (D) All of these

ILLUSTRATIVE EXAMPLE (7): The geometry with respect to the central atom of the following molecules are:   N (SiH3)3 ; Me3N ; (SiH3)3P
(A) Planar, pyramidal, planar
(B) Planar, pyramidal, pyramidal
(C) Pyramidal, pyramidal, pyramidal
(D) Pyramidal, planar, pyramidal

ILLUSTRATIVE EXAMPLE (8):
Which one of the following statements is not true regarding diborane?
(A) It has two bridging hydrogens and four perpendicular to the rest.
(B)When methylated, the product is Me4B2H2.
(C) The bridging hydrogens are in a plane perpendicular to the rest.
(D) All the B–H bond distances are equal.

ILLUSTRATIVE EXAMPLE (9):
The structure of diborane (B2H6) contains
(A) Four (2C–2e–) bonds and two (2C–3e–) bonds
(B) Two (2C–2e–) bonds and two (3C–2e–) bonds
(C) Four (2C–2e–) bonds and four (3C– 2e–) bonds
(D) None of these

ILLUSTRATIVE EXAMPLE (10):
The molecular shapes of diborane is shown:
Consider the following statements for diborane:
1. Boron is approximately sp3 hybridized
2. B-H-B angle is 180°
3. There are two terminal B-H bonds for each boron atom
4. There are only 12 bonding electrons available

Of these statements:
(A) 1, 3 and 4 are correct                                               (B) 1, 2 and 3 are correct
(C) 2, 3 and 4 are correct                                               (D) 1, 2 and 4 are correct

Assertion & Reason:

ILLUSTRATIVE EXAMPLE (11):
Statement-1 : BeH2 undergoes polymerisation while BH3 undergoes dimerisation.
Statement-2 : After dimerization of BH3 molecules into B2H6, no vaccant orbital at B
atom isleft to carry on further polymerization. However, in case of BeH2, after dimerization of BeH2molecules into Be2H4 each Be atom still contain sone empty 'p' orbital which brings further polymerization. 
(A) Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.
(B) Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation forstatement-1.
(C) Statement-1 is true, statement-2 is false.
(D) Statement-1 is false, statement-2 is true.

ILLUSTRATIVE EXAMPLE (12):
Statement-1: The B–F bond length in BF3 is not identical with that in –BF4
Statement-2: Back bonding is involved in –BF4 but not in BF3
(A) Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.
(B) Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation forstatement-1.
(C) Statement-1 is true, statement-2 is false.
(D) Statement-1 is false, statement-2 is true.

ILLUSTRATIVE EXAMPLE (13):
Statement-1: (CH3)3Si – OH is more acidic than (CH3)3C – OH.
Statement-2: (CH3)3 Si – OH has back bonding.
(A) Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.
(B) Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1.
(C) Statement-1 is true, statement-2 is false.
(D) Statement-1 is false, statement-2 is true.

Answers Key:

Monday, December 21, 2020

What are the order of extent back bonding, Lewis acid character and nucleophilicity of (BF3, BCl3, BBr3, BI3)boron trihalides?

(1) Back bonding extent in boron tri halides decreases from BF3 to BI3 because on increasing of size of p-orbital of halogens atom the strength of back bond decreases thus extent of back bonding:


(2) Lewis acid character of Boron Halides is inversely proportional to extent of back bonding because on decreasing back bonding tendency to accept lone pair from base is increases thus the order of Lewis acid character is:

Hence it is clear that BF3 is weakest Lewis acid due to stronger 2pπ-2pπ back bonding (stronger partial double bond character) in BF3 (lone pair orbital of fluorine into vacant orbital of boron) and consequently behaves as less electron deficient. The back bonding gradually decreases (From BF3 to BI3) and becomes weakest in BI3. So that BI3 become strong Lewis acid

(3) The nucleophilicity(affinity towards nucleophile/water) order is inversely proportional to the Lewis acid character thus the nucleophilicity order is:


 Related Questions: 

Why aqueous solution of AlCl3 is acidic in nature ?

What happen when aq AlCl3 react with Acid or Base?

Although anhydrous aluminium chloride is covalent but its aqueous solution is ionic in nature. Why?

Why BF3 do not exist as dimer?. Explain.

Why B-F bond length in BF3 is shorter (130 pm) than B-F bond Iength in BF4- (143 pm)?. Explain.

B-F bond length in BF3 is shorter than B-F bond length in (BF4)- why?

When B2H6 is allowed to react with following Lewis bases, then how may given Lewis base form adduct through symmetrical Cleavage of B2H6.

What is product of reaction between diborane (B2H6) and ammmonia (NH3)?

Why methylation of Diborane (B2H6) replace four hydrogen only ?

What is Use of Boric Acid?

What is use of Orthoboric acids?

What is basicity of "Boric acid" ?

Why Boric acid exist in solid state ?

What is structure of solid Ortho Boric acid ?

What is effect of heat on Borax?

What is the structure of trimetaboric acid and trimetaborate ion?

What is the Sodium per borate ,give the structure and its uses?

Why aqueous solution of borax reacts with two moles of acids ?

What is the molecular formula of Borax ?

Why Boric acid become strong acid in the presence of cis 1,2-diol or 1,3-diol ?

Why Borazine is more reactive than benzene towards Electrophic Aromatic substitution reactions ?

Why Borazine (B3N3H6) is also known as inorganic benzene ?.

Four-center two-electron bond (4C-2e Bond): Structure of AlCl3:



Friday, October 16, 2020

What is "COORDINATE BOND" ?

A co-ordinate bond formed between two species by sharing of an electron pair where shared pair electron is given by one but shared by both.

ILLUSTRATIVE EXAMPLE (1):
ILLUSTRATIVE EXAMPLE (1):
ILLUSTRATIVE EXAMPLE (1):
ILLUSTRATIVE EXAMPLE (1):
ILLUSTRATIVE EXAMPLE (1):

CONCLUSIONS:
(1)
  Atoms of second period elements follow octed rule in doing so either they accept co-ordinate bond or they form co-ordinate bond.  However atoms of 3rd period elements perfectly form double bond (pi bond) in the place of co-ordinate bond if direction of co-ordinate bond is from centre to substituent.
(2) If maximum covalency rule applied and pi bonds have formed then back bond is not considered in species
For example H2SO4 and HClO4  have no back bond there is double bond. 


What is synergic bonding 

Related Questions:


Why all the tetrahedral Complexes are high spin Complexes?

Why Fe(CO)5 is colourless while Fe(bipy)(CO)3 is intensely purple in colour ?

Why [Mn(H2O)6]+2 is colourless although in which Mn+2 ion had five unpaired electrons ?

Why [FeF6]3– is colourless whereas [CoF6]3– is coloured

Why [Ni(CN)4]-2 is colourless while [Ni(H2O)4]-2 is colour although both have +2 oxidation state and 3d8 configuration ?



Monday, December 21, 2020

Which is/are the correct statement/s about structure of methyl isothiocyanate (H3CNCS) and Silyl isothiocyanate(SiH3NCO)?

(A) CNC bond angle in H3CNCS is >120 and hybridization is closed to sp2 

(B) Si-N-C bond angle is 180 in H3CNCS
(C) Both have Back Bonding 
(D) Skeleton Si-N-C-S is linear but molecule are non planer.

SOLUTION:  

The hybridization of Nitrogen in Methyl isothiocyanate (H3CNCS) is Sp2. Thus bond angle (< C-N-C) is expected to be 120°. But it is slightly greater than 120° due to resonating structure. The resonating structure has N as sp hybridized. Hence bond angle of the overall structure is found to be about 142°


But in case Silyl isothiocyanate (SiH3NCO), the structure is found to be (sp hybridized) and planar  due to back bond between Si-N. In which the lone pair of electrons on N are donated to the vacant 3d orbitals of Si through back bonding (2pπ-3dπ back bond).



Hence Options (A, B, D) are correct.

Wednesday, July 3, 2019

Structure of phosphorous trioxide (P4O6) and phosphorous pentaoxide (P4O10) :

Phosphorous is a pentavalent element hence show +3 and +5 oxidation state (d orbital presence).it form two oxide P2O3 (+3) and P2O5 (+5). These oxide of phosphorus exist as dimer in form of P4O6 (+3) and P4O5

Comparative Study of P4O6 and P4O10 :

SN
Properties
P4O6
P4O10
1
Hybridisation (P) atom
 Sp3
Sp3
2
Hybridisation (O) atom
Sp3
Sp3 /Sp2 of Vertex (O)
3
No of Bridge bond (P-O-P)
6
6
4
No of Six member ring
4
4
5
No of Total  (l.p.)
16
20
6
No of Back Bond
0
4
7
No of P(pi)-P(pi) Bond
0
0
8
No of 2P(pi)-3d(pi) Bond
0
4
9
Longer (P-O) Bond
All are equal
12
10
Shorter (P-O) Bond
All are equal
4
11
Bond Length (P-O)
166 pm (Longer)
145 pm (shorter)
12
Bond Angle (O-P-O)
99.5 =100 (smaller)
102 (bigger)
13
Bond Angle (P-O-P)
127 (bigger)
123 (smaller)
14
No of Sigma Bond
12
16
15
No of (Pi) Bond
0
4
16
No of oxygen atom attached with( P)
3

4

Common feature of P4O6 and P4O10 :

(1) Both oxides have closed cage like structure.
(2) Both oxides contain six (P-O-P) Bond.
(3) Both oxide have 4 six member ring.
(4) Both are the anhydride of their respective acids.
(5) Both are Non planer

Explanation of Different Bond length and Bond Angle In P4O6 and P4O10 :
(1) According to "Bent's rule" lone pair electron  prefer to Stay to in those atomic hybrid orbitals have more % s-character.
(2) In case of P4O6 molecules, atomic hybrid orbitals containing lone pair electrons have more (s) character and less (p) character hence shorter bond length while remaining orbitals have less (S) character and more (p) character hence longer bond length (X1) than (X2) in P4O10 .
(3) We know that On increasing % s character in hybrid orbital, the bond length decreases while bond angle increases.
(3) In Case of P4O (O-P-O) bond angle is smaller due to higher p-character in atomic hybrid orbitals than orbital containing (O-P-O) in P4O10. (have more s-character )
For reading more Details about  click on  Bent Rule and Drago’s rule 

Related Questions:



Trisilyl amine, N(SiH3)3 is planar whereas trimethyl amines N(CH3)3 is pyramidal. Explain why?.